Answer:
Option D
Explanation:
Clearly, Kunal moves from A 10 km northwards up to B, then moves 6 km southwards up to C, turns towards East and walks 3 km up to D.
Then AC = (AB-BC)=(10-6)=4 km
CD=3 km
So, Kunal's distance from starting point A
$=AD = \sqrt{AC^{2}+CD^{2}}=\sqrt{4^{2}+3^{2}}=5 km$
D is the north east of A.